[linlan]

The Beta plans a dance as a fund raiser. The band cost $650, decoration cost $45 and the refreshment cost $2.20 per person. The admission tickets are $6 each.

What is the linear cost function
The revenue function
The profit function
How many tickets must be sold to break even
How many tickets must be sold to clear $700

[Unknown008]

What have you tried so far?

What are the costs, and what are the revenue?

Recall that profit is the difference between the revenue and the cost.

[linlan]

The Beta plans a dance as a fund raiser. The band cost $650, decoration cost $45 and the refreshment cost $2.20 per person. The admission tickets are $6 each.

What is the linear cost function
The revenue function
The profit function
How many tickets must be sold to break even
how many tickets must be sold to clear $700

Am I on the right track?
Y=C(X)=mx+b

(x2, y2) = (650, 45)
(x1, y1) = (2.20, 6)

650-45=605 = 159.2
2.20-6=3.8

[Unknown008]

Unfortunately no. The values given to you are not coordinates, they are constants, and some are associated with variables.

Costs = Band + Decoration + Refreshment.
Band is constant, $650
Decoration is constant, $45
Refreshment is $2.20 per person. Let the number of persons be x. Total cost for refreshment = 2.2x

Total cost = 650 + 45 + 2.2x = 695 + 2.2x

This is the cost function, or

C(x) = 695 + 2.2x

Now, the admission tickets is the source of revenue. Can you work out the total revenue with x people for $6 per person?

Then the profit function is given by the Revenue function minus the Cost function.

Break even is the case Profit = 0. Do that, and solve for x.

This time, the profit is $700, equate the profit equation to $700 and solve for another x.

Can you post what you get? :)

[Kiesha85]

e) 2