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    linlan's Avatar
    linlan Posts: 2, Reputation: 1
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    #1

    Feb 7, 2011, 11:06 PM
    Linear functions
    The Beta plans a dance as a fund raiser. The band cost $650, decoration cost $45 and the refreshment cost $2.20 per person. The admission tickets are $6 each.

    What is the linear cost function
    The revenue function
    The profit function
    How many tickets must be sold to break even
    How many tickets must be sold to clear $700
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Feb 7, 2011, 11:24 PM

    What have you tried so far?

    What are the costs, and what are the revenue?

    Recall that profit is the difference between the revenue and the cost.
    linlan's Avatar
    linlan Posts: 2, Reputation: 1
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    #3

    Feb 10, 2011, 07:12 AM
    The Beta plans a dance as a fund raiser. The band cost $650, decoration cost $45 and the refreshment cost $2.20 per person. The admission tickets are $6 each.

    What is the linear cost function
    The revenue function
    The profit function
    How many tickets must be sold to break even
    how many tickets must be sold to clear $700

    Am I on the right track?
    Y=C(X)=mx+b

    (x2, y2) = (650, 45)
    (x1, y1) = (2.20, 6)

    650-45=605
    = 159.2
    2.20-6=3.8
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #4

    Feb 10, 2011, 09:55 AM

    Unfortunately no. The values given to you are not coordinates, they are constants, and some are associated with variables.

    Costs = Band + Decoration + Refreshment.
    Band is constant, $650
    Decoration is constant, $45
    Refreshment is $2.20 per person. Let the number of persons be x. Total cost for refreshment = 2.2x

    Total cost = 650 + 45 + 2.2x = 695 + 2.2x

    This is the cost function, or

    C(x) = 695 + 2.2x

    Now, the admission tickets is the source of revenue. Can you work out the total revenue with x people for $6 per person?

    Then the profit function is given by the Revenue function minus the Cost function.

    Break even is the case Profit = 0. Do that, and solve for x.

    This time, the profit is $700, equate the profit equation to $700 and solve for another x.

    Can you post what you get? :)
    Kiesha85's Avatar
    Kiesha85 Posts: 1, Reputation: 1
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    #5

    Sep 17, 2012, 09:35 AM
    e) 2

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