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    Prostaff's Avatar
    Prostaff Posts: 4, Reputation: 1
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    #1

    Apr 27, 2012, 05:21 AM
    A car weighs 1000Kg and the driver applies the brakes with a force of 400N.
    Its physics. I got an answer but I'm not sure if I'm right
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Apr 27, 2012, 06:02 AM
    Quote Originally Posted by Prostaff View Post
    Its physics. I got an answer but I'm not sure if I'm right
    Your question got cut off - what are you trying to calculate, the car's rate of deceleration? Also - please tell us what answer you got and how you arrived at it, and we can tell you whether it's correct or not.
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    #3

    Apr 27, 2012, 09:27 PM
    Quote Originally Posted by ebaines View Post
    Your question got cut off - what are you trying to calculate, the car's rate of deceleration? Also - please tell us what answer you got and how you arrived at it, and we can tell you whether it's correct or not.
    Yeah, I'm trying to find the car's rate of deceleration. I got
    Time=2.5
    Velocity due to gravity=10m/s
    So deceleration=-(0-10/2.5)=4m/s^2
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    ebaines Posts: 12,131, Reputation: 1307
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    #4

    Apr 30, 2012, 05:46 AM
    To find the acceleration of the car use F=ma: F is the force applied by the brakes in the direction opposite of travel (hence is a negative number), and m is the mass of the car. So from F=ma you can rearrange to get: a = F/m = -400N/1000Kg.

    Why diid you include 'g' (acceleration due to gravity? For a car on a level road (which I assume this is) gravity acts perpendicular to the direction of motion and hence has no effect on the car's acceleration.
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    #5

    May 1, 2012, 02:18 AM
    Quote Originally Posted by ebaines View Post
    To find the acceleeation of the car use F=ma: F is the force applied by the brakes in the direction opposite of travel (hence is a negative number), and m is the mass of the car. So from F=ma you can rearrarnge to get: a = F/m = -400N/1000Kg.

    Why diid you include 'g' (acceleration due to gravity? For a car on a level road (which I assume this is) gravity acts perpendicular to the direction of motion and hence has no effect on the car's acceleration.
    Thanks for the reply. I understand it now, it was on my test and I obviously screwed it up. Thanks though

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