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pixied1993 · Mar 13, 2012, 12:29 AM

(sec(x) - tan(x))2 = 1 - sin(x)/ 1 sin(x)

ebaines · Mar 13, 2012, 05:51 AM

Please learn to use parentheses properly. And also note that you can not cut and paste equations from other applications into this site - it drops some of the characters,( such as plus signs)

I think what you meant to write is this:

(sec(x) - tan(x))^2 = (1 -sin(x))/(1+sin(x))

Start by converting the sec(x) and tan(x) functions into theire sin(x) and cos(x) equivalents. The left hand side becomes

$<br /> (\frac 1 {\cos(x)} - \frac {\sin(x)}{\cos(x)} )^2 = \frac {(1-\sin(x))^2}{\cos^2x} = \frac {(1-\sin(x))^2}{1-\sin^2x} = .....<br />$

I'm sure you can take it from here.