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    havj0y's Avatar
    havj0y Posts: 7, Reputation: 1
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    #1

    Dec 12, 2011, 11:50 PM
    Calculus 2
    The curve y=(x^3)/3 - x^2 -3x 4 has a local maximum point at P and a local minimum point at Q. Determine the equation of the straight line passing through P and Q in the form ax by c=0 where a,b,c are all real numbers
    Aurora2000's Avatar
    Aurora2000 Posts: 111, Reputation: 16
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    #2

    Dec 13, 2011, 03:52 AM
    First determine who are those points P and Q: as they are local max and min, the derivative is 0 in P and Q.




    thus x=-1, and x=3 to which correspond y=17/3 and y=-5, thus one point is (-1,17/3)
    and the other (3,-5). Thus the line passing in P and Q is



    which leads to 8x+3y-9=0.
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