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    aperrone's Avatar
    aperrone Posts: 1, Reputation: 1
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    #1

    Dec 5, 2011, 06:19 PM
    finding third force of equilibrium object
    An object in equilibrium has three forces exerted on it. A 42 N force acts at 90° from the x axis and a 46 N force acts at 60°. What are the magnitude and direction of the third force?
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    Dec 6, 2011, 07:30 AM
    Convert the 42N and 46N forces into x and y components. The third force will have x and y force components that balance out the sum of the other x and y components of the other two. Then use Pythagoras to find the total magnitude of the third force, and its angle will be the arctangent of its y component divided by its x component. Post back with your answer and we'll check it for you.
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