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incubusamok · May 4, 2011, 01:40 PM

Hi can someone help me transpose this formular I have know idea.

I want to know h out of this:
Q = 1.98 x (10^-4) x d x (h^1.5)
and
Q = 6.60 x (10^5) x (d^2) x SQRT h

Where
^ = power of
SQRT = Square root

Look Forward to hearing from you

Regards
Zuke

ebaines · May 4, 2011, 01:57 PM

Are you looking to express d as a function of Q and h? Or h as a function of Q and d?

In general you want to peform operations that get the new independent variable of one side of the equals sign all by itself. Here's an example - suppose you are given

$ Q = 1.2 \times 10^3 d^3 h^2 $

To get into a function of d, you would follow these steps:
1. Divide both sides through by $1.2 \times 10^3 h^2$ :

$ \frac Q {1.2 \times 10^3 h^2} = \frac {1.2 \times 10^3 d^3 h^2}{1.2 \times 10^3 h^2} = d^3 $

2. Take the cube root of both sides:
$ (\frac Q {1.2 \times 10^3 h^2})^{1/3} ={(d^3)^{1/3} $
Which leaves:
$ d = (\frac Q {1.2 \times 10^3 h^2})^{1/3} $

Now, can you apply this same technique to your problems?

incubusamok · May 4, 2011, 08:38 PM

Thanks for the quick reply I will have a look later today and let you know how I go

incubusamok · May 4, 2011, 08:44 PM

Thanks for that. Its rather simple. I feel silly for asking the question now.