You have a function f which maps points in 9-dimensional real space to 1-dimensional real space (i.e. a scalar). Even though it has more dimensions than you're used to working with, conceptually it's no different than a function which maps, say, two dimensional space. For example
f(x,y) = 3x - 2y + 6
maps R2 to R. For any coordinate pair (x,y), the function f(x,y) will have some real value, and it's pretty obvious that it's continuous. Changing x or y by some infinitesimal amount will result in an infinitesimal change in f(x,y).
Back to your question, since the function is simply the determinant of the matrix formed as indicated from the 9 coordinates, you can just write it out in long form:
f(a) = a1 * (a5*a9-a6*a8) - a2 * (... etc.
The determinant function is just some simple (albeit tedious) addition, subtraction, and multiplication. Like my simple 2-dimensional example, those are all continuous operations, so the function f(a) is continuous.
Does that make sense to you?
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