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bayley86 · Dec 9, 2010, 12:02 PM

A simple pendulum has a bob attached to inextensible cord 60 cm long. Determine it s frequency

Unknown008 · Dec 9, 2010, 12:16 PM

Use the formula:

$\frac{1}{f} = 2\pi \sqrt{\frac{l}{g}}$

bayley86 · Dec 9, 2010, 12:31 PM

Hi thanks for your reply could you please explain what I put into the formula and were I'm not very good at this sort of thing

Unknown008 · Dec 10, 2010, 01:59 AM

Sure, the frequency is f,
pi is a constant, which is about 3.14
l is the length of the thread, in metres
g is the acceleration due to gravity, usually taken as 9.8 m/s^2

This gives:

$\frac{1}{f} = 2\pi \sqrt{\frac{0.6}{9.8}}$

Solve for f :)

bayley86 · Dec 13, 2010, 10:48 AM

Is the answer 1.554 Hz
Thanks for your help

Unknown008 · Dec 13, 2010, 10:54 AM

No, this is the value of 1/f.

$\frac1f = 1.555$

$f = \frac{1}{1.555} = 0.643\ Hz$