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happyjoe · Dec 8, 2010, 08:17 AM

Doug hits hockey puck giving it an initial velocity of 6.0 m/s. If the coefficient of kinetic friction between ice and puck is 0.050, how far will the puck slide before stopping?

ebaines · Dec 8, 2010, 08:19 AM

Use the concept of the puck's initial kinetic energy:

KE = 1/2m v^2

equals the work done as the puck slides alomg:

W = Fd,

where F is the friction force:

F = $\mu$ mg

Solve for d.

Unknown008 · Dec 9, 2010, 12:43 AM

Or if you prefer using kinematics,

The force of friction is:

$F = \mu mg$

This gives a deceleration '-a', given by:

$F = -ma$

Thus you get:

$\mu mg = -ma$

$\mu g = -a$

Then use

$v^2 = u^2 + 2as$

Where v = 0 m/s
u = 6 m/s
a = -0.05g m/s^2
s = ? M