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kayylaa · Nov 28, 2010, 06:55 PM

y=d(x-3)^2 p : find d
step by step answer please. I really want to try and fiqure this problem out.

Unknown008 · Nov 29, 2010, 02:03 AM

Unless you have 2 points, or a graph with the relevant points indicated, you can't solve this.

kayylaa · Nov 29, 2010, 01:34 PM

oh wow I forgot to add the other number.. the function is y=d(x-3)^2+2

Unknown008 · Nov 29, 2010, 10:18 PM

Ok, I'll assume that p = 2... but you still need a last point...

ebaines · Nov 30, 2010, 07:40 AM

You can rearrange to get d by itself:

$ y = d(x-3)^2 +2 \\ y-2 = d(x-3)^2 +2 -2 = d(x-3)^2 \\ \frac {y-2} {(x-3)^2} = \frac {d(x-3)^2}{(x-3)^2} = d $

So:

$ d = \frac {y-2} {(x-3)^2} $

Per Unk's post, you can determine an actual value for d only if you have at least one (x,y) data point.