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ttoellner · Oct 13, 2010, 07:43 PM

Unknown008 · Oct 13, 2010, 09:49 PM

You can factor out 3 as a start to make the rest easier.

$27x^3-36x^2-33x-6 = 3(9x^3 - 12x^2 - 11x - 2)$

Now, let $f(x) = 9x^3 - 12x^2 - 11x - 2$

Find some factors of -2 and 9 which will make f(x) = 0.

2 seems to fit it well. So, (x - 2) is a factor. Hence, divide 9x^3 - 12x^2 - 11x - 2 by x-2

$3(9x^3 - 12x^2 - 11x - 2) = 3(x-2)(9x^2+6x+1)$

Now that you have a quadratic, you can finish it :)

Post what you get!