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shesler · Oct 5, 2010, 11:51 PM

ebaines · Oct 6, 2010, 05:51 AM

Is this what you're trying to ask?

$ 70 - \frac {48} {(n-2)^3} = 22 $
?

Please use parentheses and brackets to make it clear what order of operatons you're trying to convey.

shesler · Oct 6, 2010, 05:45 PM

no sorry... 70-(48/n-2)+3=22

ebaines · Oct 7, 2010, 05:48 AM

I assume what you mean is this:

$ 70 - \frac {48} {(n-2)} + 3 = 22 $

This is not a quadratic equation, as it does not involve a square of n. Are you sure you have the correct equation?

First thing is to group the numbers together:

$ 73 - \frac {48} {(n-2)} = 22 $

and rearrange:
$ 73 - 22 = \frac {48} {(n-2)} \\ 51 = \frac {48} {(n-2)} \\ 51(n-2) = 48 \\ 51n - 102 = 48 \\ 51n = 150 \\ n = \frac {150} {51} = \frac {50} {17} $