[Aurora_Bell]

Well, let's see the dress!

[EmoPrincess]

well, let's see the dress!

And it's only 185!
It's the dress I've dreamed of since I was a little girl

Since I can't get married in pure white since I'm not a virgin, I decided you know what, it may be red but it's beautiful. And I've always dreamed of a blood red wedding dress

[Unknown008]

Next step, using the statement

A, B, C are digits. The 3-digit number ACB is divisible by 3, BAC is divisible
by 4, BCA is divisible by 5, and CBA has an odd number of factors. Find ABC.
[3 marks]

We know that A = 5, hence, there is 5C

where C is either 2 or 6.

Using the next statement 'The 3-digit number ACB is divisible by 3'

We know that A + B + C is divisible by 3. So,
if C = 2, B = 2, 5 or 8.
if C = 6, B = 1, 4 or 7.

Then, using 'CBA has an odd number of factors'
We have either of:
225, 255, 285, 615, 645, 675

From those, we try each of them until we get an odd number of factors.

[Aurora_Bell]

Very pretty dress Emop.

[Aurora_Bell]

Next step, using the statement

A, B, C are digits. The 3-digit number ACB is divisible by 3, BAC is divisible
by 4, BCA is divisible by 5, and CBA has an odd number of factors. Find ABC.
[3 marks]

We know that A = 5, hence, there is 5C

where C is either 2 or 6.

Using the next statement 'The 3-digit number ACB is divisible by 3'

We know that A + B + C is divisible by 3. So,
if C = 2, B = 2, 5 or 8.
if C = 6, B = 1, 4 or 7.

Then, using 'CBA has an odd number of factors'
We have either of:
225, 255, 285, 615, 645, 675

From those, we try each of them until we get an odd number of factors.

That's waaay too many numbers, it makes my brain hurt just looking at it!

[Unknown008]

and it's only 185!
it's the dress I've dreamed of since I was a little girl

Since I can't get married in pure white since I'm not a virgin, I decided you know what, it may be red but it's beautiful. and I've always dreamed of a blood red wedding dress

Well, apart from the idea of the blood red coloration... it's beautiful!

Okay Bella, I'll stop :o

[EmoPrincess]

Thanks guys

And Please Unky! No more brain ouches

[Unknown008]

I said I'll stop :(

[Aurora_Bell]

Aww it's okay Unky, we're just jealous because we aren't as smart as you!

[Unknown008]

Ok, I'm tired now, see you all!

[Aurora_Bell]

Night Unky!

[Alty]

Wearing white on your wedding day doesn't signify virginity, it just signifies your first marriage.

A veil signifies virginity.

Just saying.

[hheath541]

bloody hell heath!

perhaps you were over tired to start with or your coming down with something.

we would have missed you here and sent out a search party.

I'm not really sure, but it kind of sucks knowing I almost died last night.

[hheath541]

Nah, since there are still problems that I can't solve :o

Ok, for example this one:

A, B, C are digits. The 3-digit number ACB is divisible by 3, BAC is divisible
by 4, BCA is divisible by 5, and CBA has an odd number of factors. Find ABC.
[3 marks]

I didn't solve it and had to view the solution... :(

OK, so B can be pretty much any digit. C must be an even number. A must be either 5 or 0.

since a 3-digit number cannot start with 0, none of the digits can be 0, which mean A must be 5.

5CB must be divisible by 3, while B5C must be divisible by 4. since C must be even, that leaves us with 2, 4, 6, or 8. B can be any digit but 0 at this point.

let's try A=5 B=1 C=6.
561/3=187
156/4=39
165/5=33
the only way for a number to have an odd number of factors is if it has a whole number as the square root. The square root of 516 is 22.71, so it's not our answer.

OK, so, let's try A=5 B=4 C=6
564/3=188
456/4=114
465/5=93
the square root of 546 is 23.36, so it's not our answer, either.

A=5 B=5 C=8
585/3=195
558/4=139.5 which eliminates that as a possibility

A=5 B=8 C=8
588/3=196
858/4=214.5 which eliminates that, too

OK, I'm at a loss.

[QLP]

Next step, using the statement

A, B, C are digits. The 3-digit number ACB is divisible by 3, BAC is divisible
by 4, BCA is divisible by 5, and CBA has an odd number of factors. Find ABC.
[3 marks]

We know that A = 5, hence, there is 5C

where C is either 2 or 6.

Using the next statement 'The 3-digit number ACB is divisible by 3'

We know that A + B + C is divisible by 3. So,
if C = 2, B = 2, 5 or 8.
if C = 6, B = 1, 4 or 7.

Then, using 'CBA has an odd number of factors'
We have either of:
225, 255, 285, 615, 645, 675

From those, we try each of them until we get an odd number of factors.

Doh I missed the obvious that a 3 digit number cannot begin with A being 0 so A is 5. Does having the flu count as a good excuse for being dim lol?

225 it a perfect square - odd number of factors. So A = 5, B= 2, C=2.

[DoulaLC]

here is my ring and the place he's proposing

Gorgeous ring! :)

[DoulaLC]

I'm not really sure, but it kinda sucks knowing i almost died last night.

Are you feeling even better from earlier today?

[QLP]

I have rivers of sweat running of me, this flu is making me a right old minger. ><.

[DoulaLC]

Hope you are able to get some rest QLP and feel better soon. Anything like Lemsip or tea helpful?

[Aurora_Bell]

Hey Hheath, hope you are feeling better. But you know, heat stroke is just another excuse to strip nakkie and spray yourself down with water... juts sayin'...