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objectundefined · Apr 21, 2010, 05:13 PM

[br]What is the theoretical 3d shape that is all surface area?[/br]

InfoJunkie4Life · Apr 22, 2010, 07:52 AM

I would imagine it would be a 3d fractal. Fractals are said to have an infinite perimeter. Turning it into a 3d object would be likely to have an infinite surface area.

Mandelbulb

Mandelbulb: The Unravelling of the Real 3D Mandelbrot Fractal

Clough · Jul 1, 2010, 11:49 PM

Wow! Amazing images on that website, InfoJunkie4Life!

Thanks!

objectundefined · Jul 2, 2010, 12:27 AM

Cool images, but not what I'm looking for. It's always presented as a sort of jar. A vase-shaped, glassy object that had no volume and was all surface area.

galactus · Jul 2, 2010, 02:22 AM

I think what you are referring to is called Gabriel's Horn.

If we take the unbounded region lying between the x-axis and $y=\frac{1}{x}$ , we get a solid with finite volume but infinite surface area.

The volume is given by:

$V={\pi}\int_{1}^{\infty}(\frac{1}{x})^{2}dx={\pi}$

The surface area is given by

$S=2{\pi}\int_{1}^{\infty}\frac{1}{x}\sqrt{1+\frac{ 1}{x^{4}}}dx$ .

This is an improper integral that diverges and thus shows infinite surface area.

Because $\sqrt{1+\frac{1}{x^{4}}}>1$ on the interval $[1,{\infty})$ ,

and the improper integral $\int_{1}^{\infty}\frac{1}{x}dx$ diverges,

we can conclude that the improper integral $\int_{1}^{\infty}\frac{1}{x}\sqrt{1+\frac{1}{x^{4} }}dx$ also diverges. Therefore, the surface area is infinite.

elscarta · Jul 2, 2010, 09:08 AM

While this may not be the jar you are looking for the Menger Sponge is also a 3D object with zero volume, making it all surface area.

dmcdrmtt · Aug 15, 2011, 04:15 PM

You're looking for a Klein bottle - a 3D object with no interior. http://www.google.com/search?q=klein...2&ved=0CEEQsAQ