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    kesavan's Avatar
    kesavan Posts: 118, Reputation: 1
    Junior Member
    		  
    #1

    Mar 2, 2009, 11:32 AM
    Error calculation
    I measure 20 oscillations time is 48 seconds. If the least count of that clock is 0.1 second.
    What is the error for one(single) oscillation time?
    Perito's Avatar
    Perito Posts: 3,139, Reputation: 150
    Ultra Member
    		  
    #2

    Mar 4, 2009, 05:30 PM

    48sec/20 = 2.4 sec/oscillation. The least count of the clock is 0.1 second. Therefore, I think the error in the period is 48±0.1/20 = 2.4 ± 0.005 sec/oscillation.

    If I did this wrong, I would appreciate someone telling me. It's been a while since I've done this.
    kesavan's Avatar
    kesavan Posts: 118, Reputation: 1
    Junior Member
    		  
    #3

    Mar 6, 2009, 10:28 AM

    one oscillation time is 2.4 s
    so error per single oscillation is ±0.1/48*2.4=±0.0005
    acmmanoj's Avatar
    acmmanoj Posts: 1, Reputation: 1
    New Member
    		  
    #4

    Jun 29, 2010, 11:06 PM
    This is so wrong still the error is 0.1s. Division does not produce better accurate clock ( if you r correct)
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