 |
|
| Browse | Ask | Answer | Search | Join/Login |
|
|
||||
|
This sounds like homework. We don't do homework here unless it's to play devil's advocate or to move a student along to find the answer. "In analysis of variance, the assumption of normality, constant variance and independence are usually made. Why?" Why do you think? |
||||
| Question Tools | Search this Question |
Add your answer here.
Check out some similar questions!
A random sample of 46 observations was selected from a normally distributed population. The sample mean was = 81, and the sample variance was s2 = 35.0. Does the sample show sufficient reason to conclude that the population standard deviation is not equal to 7 at the 0.05 level of significance?...
A sample of size n = 20 is selected from a normal population to construct a 95% confidence interval estimate for a population mean. The interval was computed to be (8.20 to 9.80). Determine the sample standard deviation.
Owens Orchards sells apples in a large bag by weight. A sample of seven bags contained the following number of apples: 23,19,26,17,21,24,22. a)verify that s (x-sample mean)=0 This is what I'm coming up with, I'm not sure what I'm doing wrong. Help please ...
I have two questions that I just can't figure out correctly. 1. If x-bar is 4.725 and R-bar is 0.0096, and n=4, then the UCL sub R and LCL sub R are? A. 0 and 0.022 B. 0.022 and 0 C. 0.563 and 0.563 D. 0.022 and 1.00 2 If x-bar is 4.725 and R-bar is 0.0096, and n=4, then the UCL sub x-bar...
True or False T F 1. P(X > x ) + P(X < x) + P(X = x) = 1. T F 2. If P(X > x) = 0.34 and P(X = x) = 0.10, then P(X £ x) = 0.56. T F 3. In a probability histogram, the area of each rectangle equals the probability that the random variable will...
View more questions Search
|
