Simplify log2 x = -1

Ask Experts Questions for FREE Help !

Browse

Ask

Answer

Search

Join/Login

▸ ▸ ▸ » Simplify log2 x = -1

jillksantucci Posts: 1, Reputation: 1

New Member

#1

May 5, 2010, 10:35 PM

simplify log2 x = -1

I need help simplifying log2 x = -1

Reply

Unknown008 Posts: 8,076, Reputation: 723

Uber Member

#2

May 6, 2010, 12:43 AM

I guess you mean solving:

$log_2\ x = -1$

?

Then, you need to know that if:

$log_a\ b = c$

then;

$b = a^c$

Can you try it now? Post your answer! :)

The long way round is:
$log_a\ b = c$

$\frac{log\ b}{log\ a} = c$

$log\ b = c log\ a$

$log\ b = log\ a^c$

$b = a^c$

Reply

Not your question? Ask your question View similar questions

Question Tools	Search this Question
Show Printable Version Email this Page	Search this Question: Advanced Search

Add your answer here.

Check out some similar questions!

How do I simplify this? [ 4 Answers ]

radical symbol I need to simplify this. Can anyone help?

How to simplify [ 2 Answers ]

Simplify: -2-2-3²-(-3)³

Simplify (5*6^x)+(6*6^(x+1)) ? [ 1 Answers ]

Simplifying (5*6^x)+(6*6^(x+1)) = 6*6^(x+1) but I don't know why? It could also = 6*6^(x+2) , I don't know which one is right because 2 different places are giving me 2 different answers. thanks!

How do you simplify this? [ 1 Answers ]

how to u simplify : 1+sin x _____ cos x ________ + ________ = 2sec x cos x _____ 1+ sin x

Simplify [ 6 Answers ]

I have a problem: x/ the square root of (4-x^2) x is = to 2cos theta. I was wondering if I could simplify the denominator to the square too of 4, which is 2, minus the square root of 2cos^2, which is 2cos.

View more questions Search