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    anderson17's Avatar
    anderson17 Posts: 3, Reputation: 1
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    #1

    May 3, 2010, 03:43 PM
    pre calc identities
    I don't understand how to prove that each side equals each other

    (sinθ/1-cosθ) + (1-cosθ/sinθ) = 2cscθ
    edswall's Avatar
    edswall Posts: 2, Reputation: 1
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    #2

    May 3, 2010, 07:01 PM

    Get a common denominator (sinθ)(1-cosθ) for the fractions on the left. Then the numerators of fractions of the left will add to (sinθ)(sinθ)+ (1 - 2cosθ + (cosθ)(cosθ))= 2(1-cosθ) so the added fractions simplify to 2/sinθ. This is just 2cscθ
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