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ramsdale · Apr 24, 2010, 11:01 AM

F=Foe^wt transpose to t

Unknown008 · Apr 25, 2010, 02:18 AM

Do you mean:

$F = F_o e^{\omega t}$

?

InfoJunkie4Life · Apr 25, 2010, 04:53 AM

Identities:

$log(x*y) = log(x) + log(y)$

$log(\frac{x}{y}) = log(x) - log(y)$

$log(x^y) = y*log(x)$

Pretty much the same for natural logs.

ramsdale · Apr 25, 2010, 08:47 AM

Originally Posted by Unknown008

Do you mean:

$F = F_o e^{\omega t}$

?

yes that correct but transposed to find t please

Unknown008 · Apr 25, 2010, 08:51 AM

Try it using the steps I give you.

1. Move Fo to the left so that the exponential is alone.
2. Insert log (or ln) on both sides.
3. Remove the wt as powers by the rule: $log\ a^x = x\ log\ a$
4. Divide by something to get t alone.

Can you get it? If yes, post what you get. If no, post where you are stuck. :)