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nata1618 · Apr 20, 2010, 04:16 PM

hi, I need help with this problem

(2sin^2x-1)^2 / sin^4x-cos^4x = 1-2cos^2x

InfoJunkie4Life · Apr 20, 2010, 04:53 PM

Correct me if I am wrong, your equation is:

$\frac{(2sin^2(x)-1)^2}{sin^4(x) - cos^4(x)} = 1-2cos^2(x)$

galactus · Apr 21, 2010, 02:29 AM

There are several identities to keep in mind and it falls into place.

Note that

$2sin^{2}(x)-1=-cos(2x)$

and

$sin^{4}(x)-cos^{4}(x)=1-2cos^{2}(x)$

That last one is the same as on the right side of the equation, huh? :)

nata1618 · Apr 21, 2010, 04:04 PM

Thanks...

Unknown008 · Apr 22, 2010, 10:25 AM

Um... did you really understood the last two posts! :confused:

nata1618 · Apr 22, 2010, 04:14 PM

not really? =/

Unknown008 · Apr 23, 2010, 10:52 PM

If what you asked is really what we understood, then the question you asked is not a good proof.

maburichoii04 · Aug 9, 2010, 12:06 PM

.. may I ask?. ahm, can u solve, x cube plus x squared minus 7x+5 divided by x+3?. can u get it?.