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    phys_08's Avatar
    phys_08 Posts: 22, Reputation: 2
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    #1

    Feb 17, 2010, 06:25 PM
    Ionized Solution and pOH
    A 0.057M HIO3 solution is 10.0% ionized.
    What is the dissociation constant (ka) for HIO3? And what is the pOH of the solution?
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #2

    Feb 18, 2010, 08:02 AM

    The dissociation constant is given by:



    Work out the number of moles of H+ and IO3- formed, from the given numbers, and the HIO3 left.

    From that, you can find each concentration, and thus the constant.

    Do you know how to find pH?



    Well, pH + pOH = 14, you can find pOH.
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    phys_08 Posts: 22, Reputation: 2
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    #3

    Feb 18, 2010, 10:12 PM

    The answer that I got was: a) 6.3*10^-4
    b) and the pOH is 11.18
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    Unknown008 Posts: 8,076, Reputation: 723
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    #4

    Feb 19, 2010, 04:00 AM

    While I got the constant, I got the pH as 11.75.

    [H^+] = 5.7 x 10^-3

    So, pH = - log [5.7 x 10^-3] = 2.244125144

    pOH = 14 - 2.24 = 11.75597... = 11.76
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