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    moniqueeee's Avatar
    moniqueeee Posts: 1, Reputation: 1
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    #1

    Nov 27, 2006, 07:28 PM
    Functions
    (f(fx)) = 2x +4 when f(X) = 1... how do I solve this
    asterisk_man's Avatar
    asterisk_man Posts: 476, Reputation: 32
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    #2

    Nov 29, 2006, 07:00 AM
    not 100% clear on this one but I'll take a shot :)

    I think you intended to write:
    f(f(x))=2x+4
    solve when f(x)=1
    so I'd just substitue 1 for f(x)
    f(1)=2x+4
    which is simple then:
    f(1)=2*1+4=2+4=6

    hopefully someone else will agree or disagree with this result
    worthbeads's Avatar
    worthbeads Posts: 538, Reputation: 45
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    #3

    Nov 29, 2006, 04:49 PM
    I'll have to disagree. You made a mistake. You substituted 2x for 1, when fx=1.
    asterisk_man's Avatar
    asterisk_man Posts: 476, Reputation: 32
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    #4

    Nov 30, 2006, 06:50 AM
    I'm not going to try to defend my answer since I was never really confident in it to begin with. What would you suggest for an answer?
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #5

    Nov 30, 2006, 07:29 AM
    I think you're right asterisk.
    worthbeads's Avatar
    worthbeads Posts: 538, Reputation: 45
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    #6

    Dec 2, 2006, 06:46 AM
    Quote Originally Posted by asterisk_man
    not 100% clear on this one but i'll take a shot :)

    i think you intended to write:
    f(f(x))=2x+4
    solve when f(x)=1
    so i'd just substitue 1 for f(x)
    f(1)=2x+4
    which is simple then:
    f(1)=2*1+4=2+4=6

    hopefully someone else will agree or disagree with this result
    You substituted 1 for x, when really f(x) is 1. It's just a common mistake. Unless you did something I'm not aware of, then I would be the one who is incorrect.
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #7

    Dec 2, 2006, 03:39 PM
    He substituted f(x) as 1, the OP stated f(f(x)), so that would be f(1), so he's right there I believe

    EDIT: on second thoughts I'm not so sure
    worthbeads's Avatar
    worthbeads Posts: 538, Reputation: 45
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    #8

    Dec 3, 2006, 10:03 AM
    No no no. Listen. On the right side of the simplified equation, where it said 2x+4 he substituted x for 1 so that the equation was 2*1+4, but x does not equal 1. F(x)=1
    asterisk_man's Avatar
    asterisk_man Posts: 476, Reputation: 32
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    #9

    Dec 3, 2006, 09:14 PM
    My thought process was as follows:
    substitute 1 for f(x)
    f(1)
    then I just did what I would typically expect to do when I see f(something), substitute something for x.
    again, I agree that this doesn't make me feel warm and fuzzy. I made some assumptions since I didn't see a better solution. No one has any thoughts on how else this might be solved? It seems like we can all agree that we get to f(1)=2x+4. but what's next? Maybe substituting f(x)=1 is the wrong thing to do. Ideas?
    worthbeads's Avatar
    worthbeads Posts: 538, Reputation: 45
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    #10

    Dec 4, 2006, 08:48 PM
    Ok, here's the way I see it. It said F(x)=1, or f*x=1, or fx=1. So if you were substituting for f(x) or fx, you would get 1, but you wouldn't get x=1; only fx=1. So by saying f(x)=f(1) you are incorrect.

    Because it is taking so long for me to explain, I'll do it myself.

    (f(fx)) = 2x +4 when f(X) = 1

    if fx=1, f(fx)=f(1)

    f=2x+4... f(1)=1*f=f

    In terms of "f", f=2x+4
    In terms of "x", x=-f/2+2

    That's as much as I can get out of it.

    But I have a question for the original asker. In what terms should the question be answered in?
    Capuchin's Avatar
    Capuchin Posts: 5,255, Reputation: 656
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    #11

    Dec 4, 2006, 11:18 PM
    you can't multiply around the f like that, f(x) means a function of x, it isn't a variable.

    I agree that the OP probably typed it wrong :p
    asterisk_man's Avatar
    asterisk_man Posts: 476, Reputation: 32
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    #12

    Dec 5, 2006, 12:43 PM
    Ahhh. I see where our thoughts differ now.
    You interpret f(x) as f*x but I interpret f(x) as the function f with input x.
    I agree with your result if f(x) is intended to be f*x but f(x) is just so universally "a function 'f' with input 'x'" that I have a hard time imagining that it isn't.

    I think we all agree that the OP needs to clarify but I think at this point we're the only ones who still care. :)
    worthbeads's Avatar
    worthbeads Posts: 538, Reputation: 45
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    #13

    Dec 5, 2006, 04:46 PM
    I couldn't agree more.

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