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    ankara55t's Avatar
    ankara55t Posts: 53, Reputation: 2
    Junior Member
    		  
    #1

    Dec 7, 2009, 09:15 PM
    equation work
    In NaHCO3 + HCl-----yields Na Cl + H2O + CO2,

    How can I determine whether 1.31 g of HCl would be suffiicient to react with 3.8g NaHCO3
    InfoJunkie4Life's Avatar
    InfoJunkie4Life Posts: 1,409, Reputation: 81
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    #2

    Dec 7, 2009, 10:18 PM

    Balance your equation so that your coefficients are right. Then you can use them to form a ration between the two.
    InfoJunkie4Life's Avatar
    InfoJunkie4Life Posts: 1,409, Reputation: 81
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    #3

    Dec 7, 2009, 10:18 PM
    If you need more help, post back.
    neeamy's Avatar
    neeamy Posts: 1, Reputation: 1
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    #4

    Apr 13, 2012, 08:17 AM
    if you use the balanced equation u see 1 mole of HCl is needed for 1 mole of NaHCO3 using this u can first find the formula mass of 1 mole of HCl=36.5g it will neutralise 1 mole of NaHCO3 = 84g. So if for 84g of NaHCO3 u need 36.5g of HCl for 3.8 g you need 1.65g(unitary method of arithmatic) so its not enough!
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