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    rpmacs's Avatar
    rpmacs Posts: 11, Reputation: 2
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    #1

    Nov 21, 2009, 09:04 AM
    Time 2 rockets collide
    In a test of a heat-seeking rocket, the target rocket is launched at 2000 ft/sec and the heat-seeking rocket is launched along the same flight path 12 seconds later at a speed of 3200 ft/sec. Find the times t1 and t2 of flight of the rockets until the heat-seeking rocket destroys the first rocket.
    Perito's Avatar
    Perito Posts: 3,139, Reputation: 150
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    #2

    Nov 21, 2009, 09:31 AM

    Use the equation



    Where X is the distance traveled, Vo is the initial speed, T is the time and G is the acceleration due to gravity. The distance traveled must be the same, so you can equate the distances traveled.

    You also know that T2 = T1 + 12 seconds
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #3

    Nov 21, 2009, 10:44 AM
    I think it is just meant to be an exercise in d=rt.

    2000t=3200(t-12)

    Solve for t.
    rpmacs's Avatar
    rpmacs Posts: 11, Reputation: 2
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    #4

    Nov 22, 2009, 08:27 AM

    I came up with:

    2000t=3200t-3200*12
    -1200t=-38400
    t=32 sec

    Thank you
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #5

    Nov 22, 2009, 08:53 AM
    Yes. That means the faster rocket will have been in the air for 20 seconds and the one gwetting destroyed for 32 seconds.

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