Ask Experts Questions for FREE Help !
Ask
    queennae's Avatar
    queennae Posts: 1, Reputation: 1
    New Member
    		  
    #1

    Oct 14, 2009, 11:16 AM
    Interval Notation
    how to use interval notation to find the domain?
    1.f(x) =
    1
    ___________
    (x+2) (x+1)
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
    Uber Member
    		  
    #2

    Oct 15, 2009, 12:01 AM

    Well, if you draw the graph, you'll find that there are two asymptotes, one at the line x = -2 and the other one at x = -1.

    Domain is therefore:
    f(x) < -2
    -2 < f(x) < -1
    f(x) > -1
    Clough's Avatar
    Clough Posts: 26,677, Reputation: 1649
    Uber Member
    		  
    #3

    Oct 15, 2009, 12:54 AM
    Hi, Unknown008!

    Was the answer that you gave a direct answer to the question or a way to help queennae find the answer on their own, please?

    I'm just curious and really have no idea about these sort of things.

    Thanks!
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
    Uber Member
    		  
    #4

    Oct 15, 2009, 01:01 AM

    I would have posted the shape of the graph... but that's a little difficult for me just now. My graphing program is on my 'Windows XP' section of my computer, and not on my Linux section, with which I connect to the internet. Perhaps galactus or ebaines will be able to post the graph before I do... :o
    teferi's Avatar
    teferi Posts: 0, Reputation: 1
    New Member
    		  
    #5

    Oct 15, 2009, 01:03 AM

    The domain of this question is R/(-2,-1)
    Clough's Avatar
    Clough Posts: 26,677, Reputation: 1649
    Uber Member
    		  
    #6

    Oct 15, 2009, 01:08 AM
    Quote Originally Posted by teferi View Post
    the domain of this question is R/(-2,-1)
    Hi, teferi!

    Is that also a direct answer to the question, please?

    Thanks!
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
    Uber Member
    		  
    #7

    Oct 15, 2009, 01:41 AM

    Ok, let me try this:

    Name: Test.png Views: 3462 Size: 7.4 KB

    Do you see that the graph exists for all values of x, except for x = -2 and x = -1?

    This is because when you put x = -2 in the equation, your denominator becomes zero, and 1/0 gives infinity. The same happens if you put x = -1.
Not your question? Ask your question View similar questions
 

Question Tools Search this Question
Search this Question:

Advanced Search


Check out some similar questions!

Interval Notation [ 1 Answers ]

12>6(4-2x)

Interval Notation [ 3 Answers ]

2<2x+4<10 The answer I got is: 2>2x+4 or 2x+4<10 -2>2x or 2x<6 -1>x or x<3

Interval Notation [ 1 Answers ]

I completed the problem the same way I did the other one. I think I followed the right steps. |2x-2|>4 -4>2x-2>4 add 2 to both sides -2>2x>6 divide all numbers by 2 -1>x>3 is my answer

Interval Notation [ 5 Answers ]

|5x-1|<11 Above is the problem. This is my answer. 5x+1<11 5x+1-1<11-1 5x<10 x<10

View more questions Search