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    paola818's Avatar
    paola818 Posts: 1, Reputation: 1
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    #1

    Sep 30, 2009, 10:53 AM
    proving tangent formula
    proving tangent formula
    (tangent squared theta = 1-cos squared theta over 1+cos sqared theta)
    ArcSine's Avatar
    ArcSine Posts: 969, Reputation: 106
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    #2

    Sep 30, 2009, 02:06 PM
    Do you mean?.



    If so, try evaluating both sides of the proposed equality for a random value of theta.
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #3

    Oct 1, 2009, 08:55 AM

    Are you sure this formula is correct? I can't seem to get it. I tried several ways, no success.
    ArcSine's Avatar
    ArcSine Posts: 969, Reputation: 106
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    #4

    Oct 1, 2009, 09:12 AM
    Agreed... the way I structured the equation it's definitely NOT an identity. That's why I asked Paola to run a simple 'test' with any random pick for theta... just about any angle measure would provide the counterexample to the assertion that it's an ID.

    On the other hand, maybe Paola intended a different 'setup' of the equation. Just have to stand by for that.

    Cheers
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #5

    Oct 1, 2009, 09:18 AM

    I also tried , but to no avail...
    Lightning55's Avatar
    Lightning55 Posts: 97, Reputation: 7
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    #6

    Oct 1, 2009, 03:21 PM
    Quote Originally Posted by Unknown008 View Post
    I also tried , but to no avail...
    Do you think it could be:




    That should make it easily solvable.
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #7

    Oct 2, 2009, 09:43 AM

    Yes, that is true... I wonder where the OP got that "1+" up there...
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