[merliot]

What are the probabilities of getting an a's in a deck of standar cards?

[ohsohappy]

It's not that hard if you think about it, it's a fraction. 4/52 right? 4 Aces, 52 cards in a pack.

[merliot]

Ino and the answer is 1/13 right? But in my math but at the ack of the book it says that the answer is 10/13 and not one? How come? Because I no that if I put 40 divide it by 52 its 10/13 so that's why I don't get it

[ohsohappy]

Well crap, that's weird. I wish my boyfriend was here, cause he'd know off the top of his head.

[merliot]

Well crap, that's weird. I wish my boyfriend was here, cause he'd know off the top of his head.

Or maybe the book is wrong!

[ohsohappy]

Your book was definitely wrong.

[ebaines]

what are the probabilities of getting an a's in a deck of standar cards?

Merliot - please write the question out exactly as it appears in your book. Based on the discussion in this thread there seems to be confusion over the wording of the problem.

[ballengerb1]

Based on what you ask the chances are 1 in 13. If the books says something else the question is faulty or the answer is wrong. Just because something is in print doesn't isure it correct. I visited the Chicago museum of Science and Industry yesterday and saw many examples of errors printed in their displays.

[Capuchin]

I don't know, the answer is effectively 1, but there are probably some freak manufacturing faults where no aces are included in the deck. I would suspect an answer much higher than 10/13 though.

[Unknown008]

I think too it's an error in the book. The 1/13 is very similar to 10/13, in the way that only the zero is present. Such can very easily arise when the book was written.