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    Miguel045's Avatar
    Miguel045 Posts: 6, Reputation: 1
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    #1

    Aug 22, 2009, 05:58 PM
    Rod with linear charge density.
    Can someone explain me how to setup this question? I don't really want an answer, I just want to understand how I must aproach this problem... :confused:

    A thin rod runs along the x-axis from the origin to x=L. Its linear charge density (C/m) is given by B=c(x/L)^2(sin((Pi)x/L), where c is a constant. Show that at the origin;
    E(0)=(-c/2(Pi)^2(epsilon)L)i^.

    Thank you!
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
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    #2

    Aug 23, 2009, 03:15 AM
    What is that i^. Supposed to be?

    By epsilon, I am assuming that is referring to the permittivity of free space constant, which is:

    Miguel045's Avatar
    Miguel045 Posts: 6, Reputation: 1
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    #3

    Aug 23, 2009, 05:43 PM
    Hello "i^" is supposed to be a vector...
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
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    #4

    Aug 24, 2009, 01:39 AM

    The way you posted, it seemed as "i to the power of ." You could have made it in bold, like they do in some books to show that some letter represents a vector... :rolleyes:

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