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Vi Nguyen · Jul 3, 2009, 04:35 AM

Express in cartesian form a+ib, with a,b as real numbers:

1/(1+cosβ+isinβ)

Thanks ;p

galactus · Jul 3, 2009, 08:01 AM

I assume you mean like this:

$\frac{1}{2}-\frac{tan(\frac{\beta}{2})i}{2}$

Vi Nguyen · Jul 5, 2009, 04:52 AM

No, apparently the answer is .5(1-i(sinbeta/1+cosbeta).

Originally Posted by galactus

I assume you mean like this:

$\frac{1}{2}-\frac{tan(\frac{\beta}{2})i}{2}$

galactus · Jul 5, 2009, 05:57 AM

That's the same thing. Know your trig identities?

$tan(\frac{x}{2})=\frac{sin(x)}{1+cos(x)}=\frac{1-cos(x)}{sin(x)}$