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    survivorboi's Avatar
    survivorboi Posts: 431, Reputation: 9
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    #1

    Jun 14, 2009, 10:33 AM
    i need a solution to this math
    A man went to the store to buy three things, chicken, vegetables, and bananas. The total of his spent was $20.

    Vegetables plus 9 dollars equals to the Chicken.

    (Chicken plus vegetable) then minus $16 equals bananas.

    How much is chicken, vegetable, and bananas each?

    Remember, the total of his spent was $20.


    Vegetable=V
    Chicken=C
    Banana=B

    V+9=C
    (C+V)-16=Banana


    Please give me step by step on how to solve this problems. I would like to understand the problem as well as be able to solve similar problems, so please help me. Thanks!
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
    Uber Member
     
    #2

    Jun 14, 2009, 10:40 AM

    You told us to remember that the total is $20, but you yourself forgot! :p lol.

    You also have C+V+B=20.

    Substitute second equation with the first one;

    (V+9+V)-16=B
    2V + 9 - 16 = B
    2V - 7 = B

    Use that in C+V+B=20;

    C+V+(2V-7)=20

    and C=V + 9

    (V+9)+V+(2V-7)=20

    Now, can you continue?

    Hope it helped! :)

    Maybe there's shorter way... I just did what passed in my mind.
    20shasha's Avatar
    20shasha Posts: 3, Reputation: 1
    New Member
     
    #3

    Jun 14, 2009, 11:25 AM
    Quote Originally Posted by survivorboi View Post
    a man went to the store to buy three things, chicken, vegetables, and bananas. The total of his spent was $20.

    Vegetables plus 9 dollars equals to the chicken.

    (chicken plus vegetable) then minus $16 equals bananas.

    How much is chicken, vegetable, and bananas each?

    Remember, the total of his spent was $20.


    Vegetable=v
    chicken=c
    banana=b

    v+9=c
    (c+v)-16=banana


    please give me step by step on how to solve this problems. I would like to understand the problem as well as be able to solve similar problems, so please help me. Thanks!
    I don't know am going to the fith grade in August sorry
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
    Uber Member
     
    #4

    Jun 14, 2009, 11:28 AM

    Hi 20shasha! Welcome to AMHD! :) If ou don't know a question, better not post. You post only if you know, or have a suggestion, please, OK? Take time to carefully read the rules, by clicking on HELP in your blue bar near the top right corner. Thanks.
    survivorboi's Avatar
    survivorboi Posts: 431, Reputation: 9
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    #5

    Jun 14, 2009, 12:14 PM

    LOL, hey Unknown, I really can't continue on your post, I'm sorry, I don't understand how you can simplify it if there's so much unknown (to me anyways) variables.

    This is how I got it:

    (V+9)+V+(2V-7)=20

    V+V+(2V-7)=20-9
    V+V+(2V-7)=11

    V+V+2V=11+7
    V+V+2V=18

    V+V+V=18/2

    V+V+V=6

    Now what?

    Thanks!
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
    Uber Member
     
    #6

    Jun 15, 2009, 08:35 AM

    NO!! You did a mistake... that show me that you didn't have such a solid base in maths...

    Ok, x+x= 2x, right?
    x+2x=3x, still right?
    2x+2x=4x, do you agree?

    Then, V+V+2V = ?

    Now that you've found the value of V, you can find the rest easily. In the first equation; V+9=C

    Since you got V, you can have C.

    Having V and C, you can find B through V+B+C=20, or (C+V)-16=B. You just need to substitute in your values for V and C. Got it now? Or, do you need more details?

    I hope it helped! :)
    survivorboi's Avatar
    survivorboi Posts: 431, Reputation: 9
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    #7

    Jun 16, 2009, 02:19 PM

    Lol, Thanks! Unknown, you will be perfect for my math tutor!


    =)
    Unknown008's Avatar
    Unknown008 Posts: 8,076, Reputation: 723
    Uber Member
     
    #8

    Jun 17, 2009, 07:27 AM

    LOL! :p Ask anytime! :)

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