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taniqua · May 21, 2009, 04:41 PM

3x^2+bx-5=0

Perito · May 21, 2009, 11:41 PM

I guess you want to solve the equation. Right?

$3x^2+bx-5=0$

For a general quadratic equation, $ax^2+bx+c=0$ , there are two roots given by:

$x=\frac {-b + \sqrt {b^2-4ac}}{2a}$ and $x=\frac {-b - \sqrt {b^2-4ac}}{2a}$

or, $x=\frac {-b \pm \sqrt {b^2-4ac}}{2a}$

In your case, a=3, b=b, c=-5.

Since b isn't known, I can't solve it further. If you aren't yet familiar with the quadratic equation, you'll have to supply a value for "b" so that the equation can be factored.