Check out some similar questions!

jahaira1994 · May 11, 2009, 06:03 PM

I need homework help
[F]lesson 9.6 worksheet

1. 2x^2-27x+13=
2. 2n^2+13n-7=
3. 5x^2+20t+11=
:confused:
:confused:
:rolleyes:
:confused::eek:

Perito · May 11, 2009, 08:04 PM

$2x^2-27x+13=0$

$2n^2+13n-7=0$

$5x^2+20x+11=0$

These are known as quadratic equations. One way to solve them is to factor them.

$2x^2-27x+13=(x-13)(2x-1)=0$

If the product of two numbers equals zero, then at least one of the numbers is zero. So,

$x-13=0$ or $2x-1=0$

$x=13$ or $x=-\frac 12$

The other two problems are solved in the same way.

There is also a quadratic equation that will solve them directly.

For a general quadratic equation,

$0 = ax^2 + bx + c$

The roots of the equation are given by

$X = \frac {-b \pm \sqrt{b^2-4ac}}{2a}$

jahaira1994 · May 13, 2009, 03:29 PM

Thanks for the help...