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    Aisha_18's Avatar
    Aisha_18 Posts: 13, Reputation: 1
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    #1

    Mar 4, 2009, 09:43 AM
    Redox titrations.
    How would I find the RMM of the unknown metal if the molarity of HCl = 0.1 M , NaOH = 0.1
    The Metal was dissolved in 80 cm3 of HCL and titrated against 22. 74 cm3 of NaOH. The mass of the metal was 0.0686 g.
    Perito's Avatar
    Perito Posts: 3,139, Reputation: 150
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    #2

    Mar 5, 2009, 02:02 PM

    You added 80 cc (mL) of 0.1M HCl. That is 8 mmoles.

    You back-titrated with 22.73 cc (mL) of 0.1M NaOH. That's 2.273 mmoles.

    8 - 2.273 = 5.727 mmoles

    You don't know the metal but you know that there are 5.727 milliequivalents of it present.

    5.727 milliequivalents / 0.0686 g = 83.484 milliequivalents / g

    or

    0.083484 equivalents / gram

    Now, I don't know what RMM means, so you'll have to figure that part out.
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