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    chloed's Avatar
    chloed Posts: 1, Reputation: 1
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    #1

    Jan 13, 2009, 12:23 PM
    simultaneous equations
    2x-y=6
    - x+3y=10

    solve algebraically
    Justwantfair's Avatar
    Justwantfair Posts: 3,422, Reputation: 944
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    #2

    Jan 13, 2009, 12:25 PM

    We do not complete homework on this site.
    RPVega's Avatar
    RPVega Posts: 29, Reputation: 2
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    #3

    Oct 25, 2010, 02:13 PM
    2x - y = 6
    -x + 3y = 10
    Solving for y in the top equation, we have -y = 6 - 2x; which is the same as y = 2x - 6.
    Next, substitute the value for y in the second equation, then solve for x:
    -x + 3(2x -6) = 10
    -x + 6x -18 = 10
    5x = 28
    x = 28/5. Substitute x = 28/5 into 2x -y = 6, then solving for y, yields y = (56 -30) /5 = 26/5. Good luck!
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