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    amaasd2000's Avatar
    amaasd2000 Posts: 3, Reputation: 1
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    #1

    Dec 15, 2008, 08:29 AM
    How to calculate the electrical lighting and appliance load, in single family house
    I have to calculate this in Kilowatts. The formula has to be within NEC guidelines. Using Article 220. Please simplify the formula. I just need to know kw and not kilowatt hours
    tkrussell's Avatar
    tkrussell Posts: 9,659, Reputation: 725
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    #2

    Dec 15, 2008, 09:50 AM
    Using traditional Ohm's Law:

    P (KW)= EI/1000

    Kilowatts = Volts times amps divide by 1000

    For example:

    P= 240 volts times 50 amp = 12,000 watts divided by 1000 = 12 KW

    I have to ask, and not meaning to be offensive or condensending, but if you can understand Article 220, but did not know this?

    Article 220 makes us electricians run screaming into the night, until we finally get it.
    amaasd2000's Avatar
    amaasd2000 Posts: 3, Reputation: 1
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    #3

    Dec 15, 2008, 10:46 AM
    Quote Originally Posted by tkrussell View Post
    Using traditional Ohm's Law:

    P (KW)= EI/1000

    Kilowatts = Volts times amps divide by 1000

    For example:

    P= 240 volts times 50 amp = 12,000 watts divided by 1000 = 12 KW

    I have to ask, and not meaning to be offensive or condensending, but if you can understand Article 220, but did not know this?

    Article 220 makes us electricians run screaming into the night, until we finally get it.
    I have the material, but don't fully understand it. I do go screaming into the night. I apologize for a mistake, that I may have made. My final exam is going to have us fill out a utility service load form for KW. A single family house and a multifamily dewelling. I need a simple formula to figure the load of: lighting, heating, and electrical recepticals. I apologize for not stating the question properly. Thanks for your first reply. I'm nervous about this exam.
    tkrussell's Avatar
    tkrussell Posts: 9,659, Reputation: 725
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    #4

    Dec 15, 2008, 02:25 PM
    Based on this:

    Quote Originally Posted by amaasd2000 View Post
    I have the material, but don't fully understand it.
    Then:

    Quote Originally Posted by amaasd2000 View Post
    I'm nervous about this exam.
    You should be.

    How did you get to the point of taking an exam and not understanding the material?

    What type of exam are you taking?

    If you need to fill out a utility load sheet, NEC Art 220 usually does not apply. They want real loads, not any derated as allowed by Art 220. The utility will apply their own demand factors against the actual loads you enter on the form.
    amaasd2000's Avatar
    amaasd2000 Posts: 3, Reputation: 1
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    #5

    Dec 16, 2008, 07:55 AM
    Quote Originally Posted by tkrussell View Post
    Based on this:



    Then:



    You should be.

    How did you get to the point of taking an exam and not understanding the material?

    What type of exam are you taking?

    If you need to fill out a utility load sheet, NEC Art 220 usually does not apply. They want real loads, not any derated as allowed by Art 220. the utility will apply their own demand factors against the actual loads you enter on the form.

    Thanks Again, for the help you gave me. I'm taking a nighttime adult school course. It's accellerated and you meet once a week. You don't get much time to review things. In the end it worked out.
    AVRAAMG's Avatar
    AVRAAMG Posts: 3, Reputation: 1
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    #6

    Dec 18, 2008, 03:22 AM
    Quote Originally Posted by amaasd2000 View Post
    I have to calculate this in Kilowatts. The formula has to be within NEC guidlines. Using Article 220. Please simplify the formula. I just need to know kw and not kilowatt hours
    I can help you if you are more specific.
    Can you please put your question again and guive more details what you want to do?
    Best Regards
    AvraamG
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