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    tejife's Avatar
    tejife Posts: 4, Reputation: 1
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    #1

    Dec 5, 2008, 06:36 AM
    Exponential and logarithmic functions
    Please, how do I write this expression : ln(3x + 2) + ln(x + 4) as the logarithm of a single number or expression. This is what I have done:
    ln(3x+2) + ln(x + 4)
    ln(3x + 2)(x + 4)
    3x^2 + 12x + 2x + 8
    3x^2 + 14x + 8 = 0
    Now I have no clue what to do or even if I am on the right track. Please help me.
    ebaines's Avatar
    ebaines Posts: 12,131, Reputation: 1307
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    #2

    Dec 5, 2008, 07:22 AM

    So far so good, although you seem to have dropped the "ln" that goes in front, and why did you add "=0" at the end? You're not trying to solve for x here, just put the logarithm expression into a simplified form. In other words, so far you have:

    ln(3x^2+14x+8)

    Since this is the log of a single expressoin, it seems to me you're done.
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