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    Klian's Avatar
    Klian Posts: 1, Reputation: 1
    New Member
    		  
    #1

    Oct 9, 2008, 06:03 PM
    Solving Quadratic Equations
    I need some help with this question.
    Two whole numbers differ by 3. The sum of their squares is 89. What are the numbers.
    BlackVY's Avatar
    BlackVY Posts: 823, Reputation: 154
    Senior Member
    		  
    #2

    Oct 9, 2008, 08:22 PM

    O man... I feel so stupid that I can't solve this in the quadratic method... something is wrong with me... but I know the answer to the question... a simple square table will solve it, but that's not the quadratic method... sorry...

    If someone knows the method, please tell me too... I feel so dumb and this is going to keep me up at night... :(
    galactus's Avatar
    galactus Posts: 2,271, Reputation: 282
    Ultra Member
    		  
    #3

    Oct 10, 2008, 05:19 AM
    They differ by 3:

    The sum of their squares is 89:

    Now, solve the first one for x or y and sub into the second. You have your quadratic.
    conman8888dud's Avatar
    conman8888dud Posts: 8, Reputation: 3
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    #4

    Apr 24, 2010, 06:59 PM

    x^2 + (x + 3)^2 = 89
    2x^2 + 6x - 80 = 0
    (2x - 10)(x + 8) = 0
    2x - 10 = 0 or x + 8 = 0
    x = 5 or -8
    The numbers are 5 and 8 or -8 and -5.
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