[ash23]

express the solution using interval notation and graph the solution set

(x+2)(x-3)<0

&&


(x+2)(x-1)(x-3)<0
-

[ISneezeFunny]

I'll help you out with the first one.

first, set it as an equality

(x+2)(x-3) = 0

so this means

x + 2 = 0 or x - 3 = 0

x = -2

x = 3

now, line graph

<---(-2)-------(0)-------------(3)--------->

and test out each area (so... pick -3, -1, 1, and 4), and plug in back into equation, and see if it's negative.