A boat is sailing on a course of 340T for a distance of 100km. It then makes a left turn of 10 degrees and travels for 50km

Find the new bearing and find the distance of the boat from the home.

:confused: :confused: :confused:

Help lol

A scout troop travels on a hike of 2km with a bearing of N48 E. they then turn south and travel on a bearing of S55 E and travel for 5km and camp for lunch.

How far is the camp from the starting point and find the bearing to get the scout troop back to their starting point

:confused: I hate bearings :(

Quote:

---

Originally Posted by HomeworkMan

A boat is sailing on a course of 340T for a distance of 100km. It then makes a left turn of 10 degrees and travels for 50km

find the new bearing and find the distance of the boat from the home.

:confused: :confused: :confused:

help lol

---

Look at the picture I attached. I have never heard of bearings (perhaps I just don't know the name for it in my language), but distance from home should be pretty easy to calculate from what you have, using a "Sine theorem" or "Cosine theorem".

Call the length AB "a", BC "b" and AC "c". You want to know the length of "c".

"Cosine theorem" (I guess that's what you call it in english) says:
c^2 = a^2 + b^2 - 2*a*b*cos( angle at point B )

Angle at point B = 180 - 10 (he made a 10 degrees turn) = 170 degrees
a = 100
b = 50

You have everything to calculate "c".

What crocivic said is absolutely right. You just hafta draw the triangle and plug in the data that you have. The actual name is the "Law of Cosines" but whatever. Remember, however, that a, b, and c are arbitrary names for the sides, and that any side could be a, b, or c.