OK, here's a fun little problem whose answer can be surprising -
Suppose you have two glasses of different liquids with the same amount in both - say 6 ounces of red wine in one glass and 6 ounces of white wine in another. Now if you pour exactly one ounce of the red wine into the white and thoroughly mix it, and then pour one ounce of that mixture back into the glass of red wine and mix it, you will end up with two glasses each containing 6 ounces of "contaminated" wine. The question is: after all the mixing which glass has wine that is more contaminated: the one that was originally all red or the one that was originally all white?
Post your answer, but please don't give a math proof for it - at least not yet - as that may spoil it for others...