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-   -   Anyone know how to do this (https://www.askmehelpdesk.com/showthread.php?t=86752)

  • Apr 26, 2007, 07:06 PM
    EGNW
    Anyone know how to do this
    A 1050 kg car moving south at 10.0 m/s collides with a 2650 kg car moving north. The cars stick together and move as a unit after the collision at a velocity of 5.16 m/s to the north. Find the velocity of the 2650 kg car before the collision
  • Apr 26, 2007, 10:12 PM
    Clough
    Now, that sounds like a challenge. It would be wise to read the information contained on the following link first.

    https://www.askmehelpdesk.com/math-s...board-b-u.html

    Also, what steps do you think that you should take to solve the problem? That would be helpful in providing help to you from people here who will read your post.
  • May 9, 2007, 06:58 AM
    eeseely
    A 1050 kg car moving south at 10.0 m/s collides with a 2650 kg car moving north.
    The cars stick together and move as a unit after the collision at a velocity of 5.16 m/s to the north.
    Find the velocity of the 2650 kg car before the collision
    ===========================
    This is a conservation of momentum problem where
    momentum = mass*velocity (MV)

    The north-bound car will have more momentum than
    The south-bound car.

    Given:

    1,050*10.0 = 10,500 kg m/s (going south)
    2,650*V = momentum of car going north
    (1050+2650)*(-5.16) = combined momentum going north

    HENCE:

    10500 –2650*V = (1050+2650)*-5.16

    -2560V = -19092-10500

    -2560V = -29592

    V = -29592/-2560

    V = 11.56 m/s

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