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-   -   The Quadratic Formula and Discriminant? (https://www.askmehelpdesk.com/showthread.php?t=85887)

  • Apr 24, 2007, 03:01 PM
    rocktober31
    The Quadratic Formula and Discriminant?
    :confused: :( *screams in horror*

    I seriously need help with this problem!!

    3x(squared) +1=2x :eek: this is the formula! -b + - (square root of) b(squared) - 4 ac
    all divided by 2a

    please help!! :confused:

    this is 9th grade algebra!!
  • Apr 24, 2007, 11:27 PM
    Capuchin
    You need to put it into the form ax^2 + bx + c = 0

    then you can put a b and c into the equation.

    Have a go first, we will help you further if you are still stuck.
  • Apr 26, 2007, 01:37 PM
    rocktober31
    Quote:

    Originally Posted by rocktober31
    :confused: :( *screams in horror*

    I seriously need help with this problem!!!

    3x(squared) +1=2x :eek: this is the formula! -b + - (square root of) b(squared) - 4 ac
    all divided by 2a

    please help!!!!!!!!:confused:

    this is 9th grade algebra!!!

    Okay I did that. Thanks. Before I can rate that answer, I have to spread my rep. around.

    I give it a 10 though!!
  • Apr 26, 2007, 02:03 PM
    Capuchin
    Glad I could help.
  • May 3, 2007, 06:56 AM
    Jessuka1623
    Quote:

    Originally Posted by rocktober31
    :confused: :( *screams in horror*

    I seriously need help with this problem!!!

    3x(squared) +1=2x :eek: this is the formula! -b + - (square root of) b(squared) - 4 ac
    all divided by 2a

    please help!!!!!!!!:confused:

    this is 9th grade algebra!!!

    subtract 2x from both sides so you get: (^2=squared)

    3x^2-2x+1=0

    the work the problem from there...

    2 +- sqr. root of -2^2-4*1*3
    2*2

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