Hello, I'm really struggling with this calculus homework. Please help!
According to the 2011 National Survey of Fishing, Hunting, and Wildlife-Associated Recreation, there were over 71 million wildlife watchers in the US. Of these wildlife watchers, the survey reports that 80% actively observed mammals. Suppose that one of the census workers repeated the survey with a simple random sample of only 500 wildlife watchers that same year.
Assuming that the original survey's 80% claim is correct, what is the approximate probability that between 79% and 81% of the 500 sampled wildlife watchers actively observed mammals in 2011?
a.) P(0.79< p ^ <0.81)≈0.46
b.) P(0.79< p ^ <0.81)≈0.54
c.) P(0.79< p ^ <0.81)≈0.65
d.) P(0.79< p ^ <0.81)≈0.42
