Can we construct a light bulb that matches the sun's blackbody spectrum?
Hi, I have a question for electrical engineering experts about light bulbs and producing one most like the solar blackbody spectrum. I understand that a blackbody is defined by it's surface temperature, being a thermal radiator, and the sun is at around 5700 to 6000 Kelvin. I also heard that when you heat something up to 2500 K you start producing some UV radiation, while most is visible and thermal
radiation at that temperature. It appears that Tungsten Halogen bulbs are
the only current existing bulb that heats tungsten up to temperatures of
around 3000 K and emits a blackbody spectrum like the sun. The problem again
is that there is very little UV radiation at this temperature (and I am
looking for more UV from a blackbody bulb), and so it is mainly visible and
infrared radiation, some UV-A but very little or no UV-B, and so it's a far
from perfect imitation of the solar blackbody at a temperature of 5700 K.
Now I have a more specific question. Is it possible to create a
high-intensity light bulb (similar to a halogen) that heats up some material to 5700 K (the tungsten melting point is only 3680 K so tungsten will not do it) so that it emits a larger amount of UV A and B radiation, and then filter out all the dangerous short-wave radiation (UV-C or if there are any x rays or gamma rays), leaving only the visible spectrum, the far, mid, and near infrared, and the UV A and UV B radiation only and not UV C or any other dangerous radiation? I also would want a bulb that can get to 75,000 to 100,000 lux like the sun from say 4-8 inches away (which halogens can already do), and has a good white-bluish light color just like the sun, which should be automatic if it's a blackbody at a temperature of 5700K.
Thanks if you can answer me about the practicality of a such a light bulb and if any quartz bulb could withstand the radiation of a 5700K blackbody.
Sincerely,
Tim.