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-   -   Infinity (https://www.askmehelpdesk.com/showthread.php?t=817781)

  • Nov 1, 2015, 12:15 PM
    abver
    Infinity
    If you have the sums $ (1+2+.. +n) + (1+2+3+.. +n-1)+ (1+2+3+.. +n-2)+(1+2+3+.. +n-3)+... +(1+2+3)+(1+2)+1$for large enough $n$
    $$\frac {n^3}{3!} \approx (1+2+.. +n) + (1+2+3+.. +n-1)+ (1+2+3+.. +n-2)+(1+2+3+.. +n-3)+... +(1+2+3)+(1+2)+1$$ if divided the sum by the divisor let's call it $x$ (can be any number $1,2,3.. $) we get $$\frac {n^3}{3!x^2} \approx (1x+2x+.. +\frac {n}{x}x) + (1x+2x+3x+.. +\frac {n-1}{x}x)+ (1x+2x+3x+.. +\frac {n-2}{x}x)+(1x+2x+3x+.. +\frac {n-3}{x}x)+... +(1x+2x+3x)+(1x+2x)+1x$$If the difference between the closest numbers let's call it $d$, $d=\frac {1}{10^k}$, we get $$\frac {n^3}{3!x^2d^2} \approx (1dx+2dx+3dx.. +\frac {n}{x}x) + (1dx+2dx+3dx+.. +\frac {n-d}{x}x)+ (1dx+2dx+3dx+.. +\frac {n-2d}{x}x)+(1dx+2dx+3dx.. +\frac {n-3d}{x}x)+... +(1dx+2dx+3dx)+(1dx+2dx)+1dx$$ if we assume $k\to\infty$ we get $$\frac {n^3}{3!x^2d^2} = (1dx+2dx+3dx.. +\frac {n}{x}x) + (1dx+2dx+3dx+.. +\frac {n-d}{x}x)+ (1dx+2dx+3dx+.. +\frac {n-2d}{x}x)+(1dx+2dx+3dx.. +\frac {n-3d}{x}x)+... +(1dx+2dx+3dx)+(1dx+2dx)+1dx$$ OR $$\frac {n^3}{3!x^2} = (1d^3x+2d^3x+3d^3x.. +\frac {n}{x}dx) + (1d^3x+2d^3x+3d^3x+.. +\frac {n-d}{x}d^2x)+ (1d^3x+2d^3x+3d^3x+.. +\frac {n-2d}{x}d^2x)+(1d^3x+2d^3x+3d^3x.. +\frac {n-3d}{x}d^2x)+... +(1d^3x+2d^3x+3d^3x)+(1d^3x+2d^3x)+1d^3x$$ Now if we assume that $n$ value of circle arc and $x$ value of diameter, we get $n - \frac {n^3}{3!x^2} \approx$ value of chord, So we got the first condition of Taylor series.The question is my calculations are correct?
  • Nov 3, 2015, 09:38 AM
    ebaines
    Unfortunately the LaTeX editor on this system requires the use of [math ][ and [/math] delineators, not dollar signs. I am rewriting your question here using those delineators so that it can be more easily understood:

    If you have the sums



    for large enough



    if divided the sum by the divisor let's call it (can be any number ) we get



    If the difference between the closest numbers let's call it , , we get



    if we assume we get



    OR



    Now if we assume that value of circle arc and value of diameter, we get value of chord, So we got the first condition of Taylor series.The question is my calculations are correct?
    ------------------------
    Now for my comment on your post: starting with the line "if divided the sum by the divisor let's call it " you have multiple math errors, which makes it difficult to understand what you are trying to do. I suggest you check your LaTeX nomenclature, correct the errors, and repost using the proper [math ] and [ /math] delineators for LaTeX.

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