Will it be right to say √-36=±6i? If no then please tell why.

It is correct:

Thanks!

√-36= 6i

since -36 can be written as -1*6*6 or -1*6^2
therefoe \sqrt(-36)=\sqrt(-1*6^2)
=6\sqrt(-1)
=6i {since \sqrt(-1)=i}

Quote:

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Originally Posted by Rajesh Bhuria

√-36= 6i

since -36 can be written as -1*6*6 or -1*6^2
therefoe \sqrt(-36)=\sqrt(-1*6^2)
=6\sqrt(-1)
=6i {since \sqrt(-1)=i}

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You are commenting on a post that is almost a year old. The correct answer is as shown in earlier posts. Rememeber that -36 can also be written as .