A Plane flies north at 215 km/h. A wind from the east blows at 69km/h. What is the plane's new velocity with respect to the ground in standard position




Please help me! I'm clueless. So far I have,

x=-69km/h
y= 215km/h

y/x 215/-69 = -3.11594
I'm not sure what the next step is.

Google "forward airplane velocity when flying in a sidewind".OR (numbers are different as is wind direction but still the same formula)
When directions as well as magnitudes of speeds are considered, we're into vectors. The resulting speed can be found by finding the resultant velocity via vector rules. The diagram shows a sample vector that represents the magnitude and direction of the airspeed, and another that represents the velocity of windspeed. The resultant is the diagonal of the parallelogram so formed. In this case, the parallelogram is a rectangle. The Pythagorean Theorem (c^[2 = a² + b²) gives the magnitude of the resultant. The angle can be found with a protractor, or a bit of trigonometry.

http://dev.physicslab.org/img/1ba21d...c8488830f2.gif