What is the hypotenuse of an isosceles triangle if the perimeter is 16 + 16 radical 2?
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What is the hypotenuse of an isosceles triangle if the perimeter is 16 + 16 radical 2?
The perimeter is
The hypoteneuse is
Solve for a.
Is that the final answer or does it have to be simplified?
I said "solve for a".
Oh ok, sorry I didn't see that sentence. Thank you for your help.
You're so welcome. Few that post on this site bother to even drop a line and say thanks.
Quote:
Originally Posted by galactus
Factor out 'a' and divide through.
Now, it's easy. Ain't it? Just be sure to simplify it down.
Got it. Thank you very much.
May I ask you if the answer to this is 16(1-radical2)?
Poor kid, you're sure having a time with basic algebra.
Practice simplfying this. Rationalize the denominator.
It reduces to
That's a side. Now, use that to find the length of the hypoteneuse. Should be easy.
There ya' go. ;)
Dude, relax - these people in the post are trying to get some help - no need to show off or have this rude attitude...
It's all right, I didn't know either of that when I joined, and it's through mistakes that we learn, right? :D
I just wanted to point that fact out. Thank you! :)
How do you go from the square root of a squared plus a squared to the square root of two times a. Please respond asap if at all possible.
This:Quote:
how do you go from the square root of a squared plus a squared to the square root of two times a. Please respond asap if at all possible.
becomes this:
Which then is the same thing as:
and
Therefore:
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