The problem is: 1001^2 - 999^2/101^2-99^2. How do you solve that the easy way instead of calculating and squaring the numbers? There must be an easier way of factoring since the exponents are the same?:confused:

This is difference of 2 squares.



Do this to both the numerator and the denominator.
Then you can do the additions and subtractions within the brackets easily, and the division becomes trivial.

Difference of 2 squares is VERY useful :)

How about if the equation has the same base but different exponent, like: 10^8+10^8/10^2+10^6?

There's not much you can do with addition. All the useful properties are in multiplication.

take ,

that's which you can't really get as the exponent of something else very cleanly :)

I knew it. It's hard to remember grade school algebra. I'm studying for my GMAT and I've come across the most basic mathematics and I'm used to factorials and derivatives... tee hee. THANK YOU SO MUCH FOR YOUR HELP!

(15^23+23^23) equals what

Quote:

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equals what?

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As Capuchin said, there's not much you can do with addition. The exponents are the same, but that doesn't lead to anything useful.

How do I type quadratics, surds halfs and so on on this page?

We use LaTeX. Here's a reference to it:

https://www.askmehelpdesk.com/math-s...las-50415.html

Basically, for quadratics, we simply start with "[ math ]" and end with "[ /math ]" (except leave out the spaces). For a single-numeral exponent, do x^3. For a double-numeral exponent, you need to use curly braces: x^{34}. I'm not sure what a "surds halfs" is. To do subscripts, you write X_3 or X_{32}.

There's a lot more to it. I find I frequently use fractions: \frac {x}{y} where x and y are expressions. If you simply want 1/2, it's simply \frac 12. Square roots are similar \sqrt {}.

And stop reviving threads of a year or more years old!! :mad:

To newbies: Start a thread for you, don't use another thread that another started.

50 = 2(1+r) + 2(1+r)^2 + 2(1+r)^3 + 2(1+r)^4 + 2(1+r)^5
Is there any way to simplify this in solving for r?

50 = 2(1+r) + 2(1+r)^2 + 2(1+r)^3 + 2(1+r)^4 + 2(1+r)^5
Is there any way to simplify this in solving for r?

Jeffdal: please (a) do not tag onto an old thread like this, and (b) please do not ask the same question in multiple posts. This question is asked here:
https://www.askmehelpdesk.com/mathem...-a-470584.html