What is the least number, which when divided by 48,60,72,108 and 140 leaves remainders 38,50,62,98 and 130 respectively?

Please tell me the answer and procedure to solve this problem

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Here's a hint to get you started. Suppose the answer is 'A' - note that dividing A by each of these divisors leaves a remainder that is 10 less than the divisor. Therefore all of these divisors divide into A +10 without a remainder. Hence A+10 is the least common multiple of 48, 60, 72, 108 and 140. Can you complete it now?